Coding Question

#include
int check_anagram(char [], char []);
int main()
{
char str1[1000]=”listen”, str2[1000]=”silent”;
if (check_anagram(str1, str2))
printf(“The two strings are anagram of each other\n”);
else
printf(“The two strings are not anagram of each other\n”);
return 0;
}
int check_anagram(char str1[], char str2[])
{
int first[26] = {0}, second[26] = {0}, third=0;
// Calculating frequency of characters of the first string
while (str1[third] != ‘\0’) {
first[str1[third]-‘a’]++;
third++;
}
third = 0;
while (str2[third] != ‘\0’) {
second[str2[third]-‘a’]++;
third++;
}
// Comparing the frequency of characters
for (third = 0; third < 26; third++)
if (first[third] != second[third])
return 0;
return 1;
}

#include <bits/stdc++.h>
using namespace std;
bool anagram(string str1, string str2)
{
// Get lengths of both strings
int len1 = str1.length();
int len2 = str2.length();
// If length of both strings is not same, then they
// cannot be anagram
if (len1 != len2)
return false;
// Sort both the strings
sort(str1.begin(), str1.end());
sort(str2.begin(), str2.end());
// Compare sorted strings
for (int i = 0; i < len1; i++)
if (str1[i] != str2[i])
return false;
return true;
}
// Driver code
int main()
{
string str1 = “listen”;
string str2 = “silent”;
if (anagram(str1, str2))
cout << “The two strings are anagram of each other”;
else
cout << “The two strings are not anagram of each other”;
return 0;
}

import java.io.*;
import java.util.Arrays;
import java.util.Collections;
class LFC {
static boolean anagram(char[] str1, char[] str2)
{
// Get lenghts of both strings
int len1 = str1.length;
int len2 = str2.length;
// If length of both strings is not same,
// then they cannot be anagram
if (len1 != len2)
return false;
// Sort both strings
Arrays.sort(str1);
Arrays.sort(str2);
// Compare sorted strings
for (int i = 0; i < len1; i++)
if (str1[i] != str2[i])
return false;
return true;
}
/* Driver program to test to print printDups*/
public static void main(String args[])
{
char str1[] = { ‘l’, ‘i’, ‘s’, ‘t’, ‘e’, ‘n’ };
char str2[] = { ‘s’, ‘i’, ‘l’, ‘e’, ‘n’, ‘t’ };
if (anagram(str1, str2))
System.out.println(“The two strings are”
+ ” anagram of each other”);
else
System.out.println(“The two strings are not”
+ ” anagram of each other”);
}
}

def anagram(str1, str2):
# Get lengths of both strings
len1 = len(str1)
len2 = len(str2)
# If lenght of both strings is not same, then
# they cannot be anagram
if len1 != len2:
return 0
# Sort both strings
str1 = sorted(str1)
str2 = sorted(str2)
# Compare sorted strings
for i in range(0, len1):
if str1[i] != str2[i]:
return 0
return 1
# Driver program to test the above function
str1 = “listen”
str2 = “silent”
if anagram(str1, str2):
print (“The two strings are anagram of each other”)
else:
print (“The two strings are not anagram of each other”)

function anagram($str1, $str2) 
{ 
if (count_chars($str1, 1) == count_chars($str2, 1)) 
return 'The two strings are anagram of each other'; 
else 
return 'The two strings are not anagram of each other';        
} 
// Driver code 
print_r(anagram('listen', 'silent')."\n");